No Multi-staged rockets are used when it is launched. Did you understand my explanation? Also the middle part was incorrect so you would've lost some marks.
I don't think so :/ wouldn't dumping empty fuel tanks allow for greater acceleration in the upward direction ?
You're thinking about it wrong. Fair enough you would get a greater acceleration but since we attempt to reduce g force as much as possible we waste all the fuel in one tank rather than using one tank for the whole journey as this would provide a constant acceleration according to
Ohhhh so if we are constantly burning fuel from the same rank the whole way , the ship would be experiencing too many g's causing a black out. Hence dumping them will keep the acceleration at a constant level instead and that constant acceleration would be under say 6 g's to stop people's dyingYou're thinking about it wrong. Fair enough you would get a greater acceleration but since we attempt to reduce g force as much as possible we waste all the fuel in one tank rather than using one tank for the whole journey as this would provide a constant acceleration according toSo what we do is we waste all the mass in one and the acceleration rapidly decreases. When it is at reasonable levels we use the next tank so that the people don't die.
Since
1+a/g confused the crap out of me. I used sigma(a)/g where the sum of all forces could only be from gravity and thrust (i.e. no 'normal reaction'). So on Earth's surface I treated sigma(a) as 9.8 instead.You're thinking about it wrong. Fair enough you would get a greater acceleration but since we attempt to reduce g force as much as possible we waste all the fuel in one tank rather than using one tank for the whole journey as this would provide a constant acceleration according to
Since
No ahaha. We don't even know if we could lift off with such low acceleration. We use it so that its as if you have tiny rocket launches throughout the journey. From A to B we have one rocket launch and when the fuel stops being used it stops accelerating and a reduces drastically reducing the g forces experienced. From B to C we have another rocket launch which starts from basically 0 acceleration... Lets say that the acceleration of A to B is X and B to C is also X. The max g force experienced would be =
To add to this, the reason why it is sometimes plus or minus is because the acceleration (a) is a vector. If can be either pointing downwards which is negative and why it is negative in your first example, or it can be pointing upwards which is why it is positive in your second example.
Although that's the most accurate interpretation, when I think about that I get confused. I'm just saying instead I actually imagine we are accelerating at 9.8ms^-2 right now instead.
We call the formula Newton's Law of Universal Gravitation. Also, it's every action will have an equal and opposite reaction, so be careful of this. I'll let someone else put on a mark.
3/4! Marking criteria says to don't forget to make a judgement of the statement at the end