How to do this question? (1 Viewer)

malcolm21 · Oct 21, 2015

InteGrand · Oct 21, 2015

malcolm21 said:

$Since the region is \textsl{below} the line $y=x-2$, the region must satisfy $y\leq x-2$, so the only options to consider now are (A) and (C). Note that the point $(x_0,y_0)=(3,0)$ lies in the region, and $y_0^2 = 0^2 = 0$, $4-x_0 = 4-3 = 1$, so $y_0^2 < 4-x_0$ (as $0<1$), so the region satisfies $y^2 \leq 4-x$. Hence the answer is (A).$

keepLooking · Oct 21, 2015

Try closing Steam, might make you work more productively.

How to do this question? (1 Viewer)

malcolm21

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InteGrand

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keepLooking

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