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Polynomials (2 Viewers)

kawaiipotato

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InteGrand

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kawaiipotato

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http://4unitmaths.com/sbhs2002.pdf
Q6 (a) (iii)
There's no solutions and couldn't find my mistake. I got a result that contradicted theirs (I got k<0 for 3 real roots)
Can someone help spot my mistake?
--
(ignore the first 5 lines)
 
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atargainz

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kawaiipotato

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did some algebra wrong finding delta 16-12(4-k) (not sure if that would change the outcome though, didn't try, just had a quick skim)
Yep the sign of k changes. Thanks :punch:

Can someone show me how to do Q8 (a) (i)?
 

integral95

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I don't think the roots of the derivative having opposite signs would imply the original function having 3 real roots,

It should be the stationary points with the y-values being opposite in signs giving 3 roots.

EDIT: besides the better method is to draw the graph k/x, one case where k>0 and k<0 and observe the intersection with the graph you drew
 

kawaiipotato

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I don't think the roots of the derivative having opposite signs would imply the original function having 3 real roots,

It should be the stationary points with the y-values being opposite in signs giving 3 roots.
Oh yeah. I should've subbed those roots into y.
That seems long, is there another method?
 

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