B brownie46 New Member Joined Oct 13, 2015 Messages 6 Gender Undisclosed HSC N/A Oct 13, 2015 #1 y4-15y²-44=0 find y
J jgaw99 New Member Joined Oct 12, 2015 Messages 11 Gender Male HSC 2016 Oct 13, 2015 #2 Wrong thread - but here goes you should quadratic formula to get a solution for y^2. Then discard the negative solution. Take positive/negative square root for solutions for y.
Wrong thread - but here goes you should quadratic formula to get a solution for y^2. Then discard the negative solution. Take positive/negative square root for solutions for y.
Z Zen2613 Member Joined May 22, 2015 Messages 172 Location Kirraymearonulla Gender Male HSC N/A Oct 14, 2015 #3 brownie46 said: y4-15y²-44=0 find y Click to expand... Assuming you meant y^4 - 15y^2 - 44 = 0 Solutions for y: y = (+/-)sqrt((15+sqrt(401))/2) y = (+/-)i*sqrt((sqrt(401)-15)/2) Where sqrt(x) is the square root function and i is the imaginary unit. #4Unit
brownie46 said: y4-15y²-44=0 find y Click to expand... Assuming you meant y^4 - 15y^2 - 44 = 0 Solutions for y: y = (+/-)sqrt((15+sqrt(401))/2) y = (+/-)i*sqrt((sqrt(401)-15)/2) Where sqrt(x) is the square root function and i is the imaginary unit. #4Unit
