Parametrics (1 Viewer)

Joshmosh2 · Dec 20, 2014

The straight line y = mx+b meets the parabola x = 2At, y= At^2 in real distinct points P,Q which correspond respectively to the values t = p, t = q
a. prove that pq = -b/a

I'm sure the solution is really simple, but I can't see it.

FrankXie · Dec 20, 2014

Joshmosh2 said:
The straight line y = mx+b meets the parabola x = 2At, y= At^2 in real distinct points P,Q which correspond respectively to the values t = p, t = q
a. prove that pq = -b/a

I'm sure the solution is really simple, but I can't see it.

$sub. $ x=2at $ and $ y=at^2 $ into $ y=mx+b. $ this leads to a quadratic equation about $ t, $ which should have two roots $ t=p $ and $ t=q. $ finally product of roots concludes the proof.$

Parametrics (1 Viewer)

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