To prove : Triangle ABC is isosceles given that AD and BE are angle bisectors, AD = BE
My Proof:
angles EAD and DAB = x ( AD bisects the angle A)
angles DBE and EBA = y (EB bisects the angle B)
and since AD = EB Given
AB = AB (common)
Does that mean x and y are equal because the they are between to corresponding sides (SAS??)
Picture down below
My Proof:
angles EAD and DAB = x ( AD bisects the angle A)
angles DBE and EBA = y (EB bisects the angle B)
and since AD = EB Given
AB = AB (common)
Does that mean x and y are equal because the they are between to corresponding sides (SAS??)
Picture down below