Jelly Beans (1 Viewer)

[Speed6]

Hi there so there is a jelly bean guessing competition at my school and it has awesome prizes to giveaway. So the jellybeans are hidden away in a rectangular tool box which I have included the link to below, I have done some research into the tool box which the jelly beans are hidden in and I think I may have hit the jackpot (no not the no. of jellybeans), (they say they bought the toolbox from bunnings) and it looks exactly alike. My question is, is there way that you can work out the no. of jellybeans in the toolbox from like a custom formula or some manipulation etc lol. I actually had a feel of the box and its has quite a substantial number of jelly beans (- 3cm from the top of the case) so its not full all the way to the top only ~3cm gap as I said.

Thanks in advance!


http://www.bunnings.com.au/tactix-400mm-tool-box_p5820715

 

[Queenroot]

I would find the volume of the container and roughly find the volume of one jellybean, then divide and see how many would fit into the toolbox.

 

[astroman]

find the volume of tool box
find the volume of each jellybean
divide volume of tool box by volume of jellbean

 

[Speed6]

I would find the volume of the container and roughly find the volume of one jellybean, then divide and see how many would fit into the toolbox.

you reckon you can help if you have some time for extra procrastination?

find the volume of tool box
find the volume of each jellybean
divide volume of tool box by volume of jellbean

Can you please help me find it lol!!!

 

[seventhroot]

I would find the volume of the container and roughly find the volume of one jellybean, then divide and see how many would fit into the toolbox.

find the volume of tool box
find the volume of each jellybean
divide volume of tool box by volume of jellbean

this probably would't work because you are assuming that there are no spaces between them. Also they might not fill it all the way etc.

 

[Speed6]

this probably would't work because you are assuming that there are no spaces between them. Also they might not fill it all the way etc.

- like 20% because of volume (gaps or air) can this be correct?

 

[astroman]

this probably would't work because you are assuming that there are no spaces between them. Also they might not fill it all the way etc.

soz but we only do/did 2u -.-

 

[seventhroot]

- like 20% because of volume (gaps or air) can this be correct?

hmm; I would be thinking more along the lines of 10%?

soz but we only do/did 2u -.-

that doesn't look like 4 unit to me

 

[Speed6]

Drongoski!!!!!

 

[integral95]

good luck

 

[Speed6]

good luck

If you help me i will give half the jelly beans to you expressed posted, zipped, locked and sweet to your door.

I will also give you tracking + insurance for up to ($10 000)

Jokes I will eat them all myself and be a fat cunt

 

[Speed6]

Im counting on you brother, take your time...

 

[Queenroot]

hmm; I would be thinking more along the lines of 10%?




that doesn't look like 4 unit to me

yeah 10% error

so do what I said and then discount it by 10%

 

[Speed6]

yeah 10% error

so do what I said and then discount it by 10%

Can you do all the calculations for me?

Please

 

[Queenroot]

Can you do all the calculations for me?

Please

nigga
it's as simple as using a calculator
ceebs

or give us values

 

[seventhroot]

Can you do all the calculations for me?

Please

plug into this formula

 

[Speed6]

plug into this formula

How did you work out that formula?

 

[Speed6]

nigga
it's as simple as using a calculator
ceebs

or give us values

w:225 h:207 l:400

 

[seventhroot]

How did you work out that formula?

well 10% error implies 90% of it is there so multiply your answer by 0.9

 

[Queenroot]

w:225 h:207 l:400

lbh = 225 x 207 x 400

Jellybean = ~27/8 cm^3

lbh/jellybean = some answer

some answer x 0.9 = Final amount of jellybeans