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HSC 2014 MX2 Marathon (archive) (1 Viewer)

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Tugga

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Re: HSC 2014 4U Marathon

Did it a different way by letting w=x+iy and simplifying z, to get z=i(y/(1-x))=+-i(sqrt((1-x)/(1+x)), which for -1(lessthan)x(lessthan)1 ,draws out the imaginary axis with a hole at origin.

Like your solution better though :p

edit: how do you use less than signs without stuffing up...
 
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Kurosaki

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Re: HSC 2014 4U Marathon

Did it a different way by letting w=x+iy and simplifying z, to get z=i(y/(1-x))=+-i(sqrt((1-x)/(1+x)), which for -1(lessthan)x(lessthan)1 ,draws out the imaginary axis with a hole at origin.

Like your solution better though :p

edit: how do you use less than signs without stuffing up...
Do you mean in Latex o_O
You just do <
 

Fizzy_Cyst

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Re: HSC 2014 4U Marathon

Four digits numbers are formed from the digits 1,2,3,4. Each digit is only used once. What is the sum of all the numbers that can be formed?
 

Fizzy_Cyst

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Re: HSC 2014 4U Marathon

Ruse's multiple choice for trials
Was it? I got it from Normanhursts trial from this year. It was Q10. Perhaps they used the same paper?

EDIT:

just checked -- a couple of MCQ's the same, but that is it
 
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