Isn't it a spiral?That is a somewhat confusing question.
"The distance of the point from 0 is between -pi and pi"
Since the distance cannot be negative, we revise the statement.
"The distance of the point from 0 is between 0 and pi"
It is a shaded circle of radius pi.
On second thought, I am quite sure my notion of the infinitely tight spiral (or more accurately infinitely many concentric circles) is correct.Isn't it a spiral?
Isn't it a spiral?
Thanks!Actually yes you are correct.
I had thought of it as an 'infinitely tight' spiral, which made a shaded circle.
But I'm sure that was the implication. I think its just a poorly worded question.There is no mention that the point has to take on the same argument as theta.
Isn't that the graph of r = | theta | ?Thanks!
The answer has this :
But how do u know how to sketch it?
when i put in wolfram "r = theta" i geetBut I'm sure that was the implication. I think its just a poorly worded question.
Isn't that the graph of r = | theta | ?
Ahh okay, that makes sense.That's because they understand R and theta to be Rcis(theta).
But the given question makes no mention of 'cis' or cos+isin.
R is the usual definition of R, which is distance from the origin.
But theta had no attached definitions as the argument. It is simply defined as a number that ranges from -pi to pi. We could have used 'x' for all we care.
The shape you got from Wolfram is the process of a spiral gone up to pi, then it 'rotates backwards' to satisfy the -pi, if that makes sense.