• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

2U Math Exam (1 Viewer)

RamizG

New Member
Joined
Mar 9, 2012
Messages
16
Gender
Male
HSC
2013
Can someone please explain how they found the area of the trapezium in question 12 b in the maths 2 U exam ?
 
Joined
Aug 28, 2013
Messages
131
Gender
Male
HSC
2013
A= h/2(P1+P2)

the heigh was the perpendicular distance from B to AC (or whatever) found in an earlier part

P1 and P2 are the two parallel sides....you know the co-ordinates of two of the top two points...so use the distance formula to find the length

for the bottom parallel line....you find the length of the whole interval and then halve it (since it was a mid-point)

I'm telling this off the top of my head-dont have the question in front me....
 

RamizG

New Member
Joined
Mar 9, 2012
Messages
16
Gender
Male
HSC
2013
A= h/2(P1+P2)

the heigh was the perpendicular distance from B to AC (or whatever) found in an earlier part

P1 and P2 are the two parallel sides....you know the co-ordinates of two of the top two points...so use the distance formula to find the length

for the bottom parallel line....you find the length of the whole interval and then halve it (since it was a mid-point)

I'm telling this off the top of my head-dont have the question in front me....
I did that, I was just making sure that the height was the perpendicular distance which was 20 right? and the area was 200?
 
Last edited:
Joined
Aug 28, 2013
Messages
131
Gender
Male
HSC
2013
I did that, I was just making sure that the height was the perpendicular distance which was 20 right? and the area was 200?
Yea, the area was 200...

It was 0.5 * (15+5) * 20 = 200

Yes the height was 20
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top