yes16a is 2x^2 -3x+1 right?
-2 at the end....16a is 2x^2 -3x+1 right?
Correct16a is 2x^2 -3x+1 right?
Y = 3 not 0-2 at the end....
Because the gradient=5 when x=2...
and when x=2, y=0
so integrate f'(x) to get f(x).....sub in 0 and 2...to get C...and C=-2
At least that's what I did....correct me if I'm wrong
y=5x-7 is a tangent to the curve...at x=2....so when x=2 y=0.....where am I wrong....someone spell it out for me...When x =2, y=3 for the y=5x-7
same haha. i got 40 months. What did u get?with b) iv.
I got the derivative of N and set it equal to dP/dt (which is probably 2/3 marks), but I couldn't work out how to eliminate P.
Yep I did that too!with b) iv.
I got the derivative of N and set it equal to dP/dt (which is probably 2/3 marks), but I couldn't work out how to eliminate P.
what did u get as your months?Yep I did that too!
I couldn't eliminate P, so I didn't get an answer (and pens down before I had time to make one up). How did you get 40?same haha. i got 40 months. What did u get?
I didn't solve it. I just derived N, and set it to dP/dt.what did u get as your months?