Re: HSC 2013 2U Marathon
![](https://latex.codecogs.com/png.latex?\bg_white Domain: \ -3 \le x \le 3)
![](https://latex.codecogs.com/png.latex?\bg_white Range: \ 0 \le y \le 3)
It is a semicircle with a radius of 3.Domain: -4 < x < 4
Range:All real y
??
It is a semicircle with a radius of 3.Domain: -4 < x < 4
Range:All real y
??
Oh yeah I didn't see thatIt is a semicircle with a radius of 3.
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Haha no problem. Hmm that boundary would also include the numbers in between 3 and 4 (i.e. 3.1, 3.2 etc.) so I don't think its right.Oh yeah I didn't see thatisn't -4 < x < 4 the same as -3<= x <= 3 or am I going full retard?
edit: probs would've saw that if it was in latex lol
*Full retard mode activated*Haha no problem. Hmm that boundary would also include the numbers in between 3 and 4 (i.e. 3.1, 3.2 etc.) so I don't think its right.
Dom 2 < x < 3 including
I didn't assume.. The last function value at f(last)= 0how did you assume this was zero?
Yea well doneDom 2 < x < 3 including
Range: 0 < y < 1 including
??
Look at the graph/ garden. Then look at the last 5th function value it's on ground point with f(last) so it's =0yeah but where did you get zero?
Yea correct
1-cosx= sin^2(x)/cos(x)Yea correct
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(this one is different I assure you)
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Not quite1-cosx= sin^2(x)/cos(x)
Cos(x) - cos^2(x)= sin^2(x)
Sin^2(x) + cos^2(x)=1
Hence, cos(x)=1
X=0![]()
X=pi/2 my badAre you allowed to put 0 in the RHS?
Your first line isn't right.1-cosx= sin^2(x)/cos(x)
Cos(x) - cos^2(x)= sin^2(x)
Sin^2(x) + cos^2(x)=1
Hence, cos(x)=1
X=pi/2![]()
Still not thereX=pi/2 silly mistake