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BOS Trials 2013 2 Unit Discussion Thread (3 Viewers)

JT145

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Oh man. I felt so happy when I got the trig proof out. Was probably the only 2 mark question in the whole paper that I got right.

I remember nailing the sine rule question on Q 16 as well.
 

Carrotsticks

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Oh man. I felt so happy when I got the trig proof out. Was probably the only 2 mark question in the whole paper that I got right.

I remember nailing the sine rule question on Q 16 as well.
Hehehe, almost seems TOO easy doesn't it?

Almost as if there's something that most students would miss out on...
 

JT145

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Where in relation to the room were you guys sitting

I was sitting right up the front, the Asian in the grey shirt and pants. The guy who arrived at 2:55.
 

Trebla

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Oh crap, I knew it seemed too good to be true

Let me guess, using the sine rule can give 2 solutions right? :(
FYI I think this year's questions (especially 2U and Ext1) had a lot of 'traps' where students think they got the right answer when really they either got it wrong or only partially correct.
 

RealiseNothing

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Where in relation to the room were you guys sitting
Across from this guy

I seriously skipped 1/2 of that, and of the half that I did do, i'd say I would have screwed up 1/2 of it! Aiming for a solid 25%! :O That goodness the HSC papers are pretty similar for year to year. I.e Same questions, just worded differently! :D
 

Makematics

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FYI I think this year's questions (especially 2U and Ext1) had a lot of 'traps' where students think they got the right answer when really they either got it wrong or only partially correct.
Yep, i got tricked badly by Q9 MC in 3U :lol:
Any others from 3U?
 

Makematics

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Where in relation to the room were you guys sitting

I was sitting right up the front, the Asian in the grey shirt and pants. The guy who arrived at 2:55.
I sat next to the guy with the snapback. The hardest part of the day was not understanding the insane maths questions, but understanding why one would wear a snapback during a maths test.
 
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Yep, i got tricked badly by Q9 MC in 3U :lol:
Any others from 3U?
Stuffed up Q8 in the MC as well :(
Did not think of letting the derivative be equal to zero for the limiting population in Q13 c) ii., I copied the wrong integral in Q13 b) iii, gave up on the projectile motion question + made tons of other sillies/skipped marks due to time urgh

edit: oops, just realised this is the 2U thread
 
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Trebla

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Not for a while. If you have any particular questions you want solutions to now then I'll put them up.
 

JT145

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I sat next to the guy with the snapback. The hardest part of the day was not understanding the insane maths questions, but understanding why one would wear a snapback during a maths test.
There were actually more Asian people than I thought

Probs all doing 4U though

I have that sinking feeling that I was probably the only person that was doing just 2U at that exam

inb410%
 

iBibah

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There were actually more Asian people than I thought

Probs all doing 4U though

I have that sinking feeling that I was probably the only person that was doing just 2U at that exam

inb410%
nah you weren't, there were others.
 

RealiseNothing

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14 b) iv - v - vi :D
14)b iv) y=mx passes through the origin. If you want to enclose an area you have to have 2 intersection points between the line y=mx and the curve

You can do this two ways, either find the gradient of the tangent to f(x) at x=0 then let m < gradient or solve the equations simultaneously and let the discriminant be positive for 2 solutions (i.e. 2 intersections). If you do the latter you will get a cubic, but note x=0 is an obvious solution so divide by x and get a quadratic.
 
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integral95

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14)b iv) y=mx passes through the origin. If you want to enclose an area you have to have 2 intersection points between the line y=mx and the curve

You can do this two ways, either find the gradient of the tangent to f(x) at x=0 then let m < gradient or solve the equations simultaneously and let the discriminant be positive for 2 solutions (i.e. 2 intersections). If you do the latter you will get a cubic, but note x=0 is an obvious solution so divide by x and get a quadratic.
Yup I recall doing the latter, (except I think I stuffed up the algebra cause I was kinda tired)
 

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