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anomalousdecay

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First of all, you only win rep for this contest.

I need some help in creating a really challenging integral of 4-unit work.

THE ANSWER MUST RESULT IN 79.9.

I will decide the winner on Sunday 8/09/13, 6pm.

So far I have this: MSP70151effg2fg4cdf62e5000060a9agefh8gh9f9g.gif

I completely made this up today from scratch. Does this even equal 79.9? :lol:
 

anomalousdecay

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I need to dedicate a memory to someone I know at school, and the number 79.9 is very significant.
 

Sy123

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(are we allowed to do only approximations?)

Make sure that when doing this integral, if you do a substitution, make sure you substitute in the exact value
 
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anomalousdecay

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Sorry man, your integral is incorrect.
Checked via wolfram alpha + my own integration+differentiation calculator (Took the calculator 30 sec to calculate LOL)
It took me 20 minutes in Economics today to make that question from scratch lol.

Never mind. It is like 17.87
 
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Sy123

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Lol no way, I worked backwards, I decided to get a relatively alright integral, which was quite short, I plugged in numerous values into wolfram alpha, and settled with 83.9 and 4. Then I substituted in something to the 'simple' integral to make it much more complex, then some manipulation. The really weird numbers for limits is due to the substitution itself.

It should end up with like 79.897....

I'll try to do another one, but I doubt it will be possible to make the integral look as though it won't simplify to 79.9.
I think the best integrals will be so that its not obvious that its going to evaluate to 79.9 (for example look at your integral, the 79.9 itself is present :p)
 
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integrate from ln(34e^5/1561) to ln(2e^5) 2dx/(5-x)(46.5-ln(5-x))

woops answer results in 2ln79.90, does that matter?
 
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anomalousdecay

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The winner is Sy123. His integral was as succinct and complex as possible.
(Oops should have added the fact that it must be short enough to be written on 10cm by 10cm paper).
 

anomalousdecay

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Was I at least even considered?
No, but have some free rep for being a HSC student coming to this thread.

Also, it is evident you only speak maths sufficiently, because you did not read that it must be an integral, so that deserves some free rep too.
 
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Squar3root

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No, but have some free rep for being a HSC student coming to this thread.

Also, it is evident you only speak maths sufficiently, because you did not read that it must be an integral, so that deserves some free rep too.
Where does it say it must be an integral?
 

RealiseNothing

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