Coordinate Geometry (1 Viewer)

[Menomaths]

Hey guys, I'm stuck on this question;
Find the equation of the straight line passing through -2,3 and making an angle of 53'8' with the x-axis.
Thanks.

 

[HeroicPandas]

Apply the one-point gradient formula or point-gradient formula (w/e its called lol)

U need a POINT and the GRADIENT

(-2,3) (yes! we have a point!)

Now, gradient.... m.... we dont have it, so we must recall that m = tan(theta) = tan(53'8')

And there u have it, a point and the gradient, enough to find the line!

 

[Menomaths]

Apply the one-point gradient formula or point-gradient formula (w/e its called lol)

U need a POINT and the GRADIENT

(-2,3) (yes! we have a point!)

Now, gradient.... m.... we dont have it, so we must recall that m = tan(theta) = tan(53'8')

And there u have it, a point and the gradient, enough to find the line!

Lol spoonfeeding me,
I know all that but my answer is coming out wrong haha

 

[HeroicPandas]

y - 3 = tan(..) (x + 2)

y = 1.33...x + 5.66...

y = 1.3x + 5.7

 

[Menomaths]

Precisely what I got, but it's wrong.

 

[pdang]

what is the answer supposed to be?

 

[RealiseNothing]

Precisely what I got, but it's wrong.

What's the 'supposed' answer?

 

[RealiseNothing]

what is the answer supposed to be?

hahahahah wow

 

[Menomaths]

4x-3y+17=0

 

[RealiseNothing]

4x-3y+17=0

That is the same answer that you got lol.

 

[pdang]

same thing. multiply both sides by 3 then move the y over. the form they gave you is the general form and the answer you got is the gradient-intercept form.

 

[RealiseNothing]

So becomes

Times everything by 3:

 

[Menomaths]

Oh that's so stupid... -.-' wasted my time on a correct answer, that's a first lol