MedVision ad

3 Complex Numbers Questions - HW Help (1 Viewer)

iPhone4

Member
Joined
Nov 7, 2011
Messages
167
Gender
Undisclosed
HSC
N/A
Hi everyone, I received a massively long assignment on C.N. this week and can't seem to get the three questions here (the ones with the black stars next to them). Could anyone help a fellow MX2'er out here? You'll practice your own skills! :) The image is attached because I CBF to be bothered to type it up on latex, and find it easier to type on word. :p



THANKYOU!

Edit: Question 2C says: If z=costheta + isintheta, show that for sin(theta/2) cannot equal zero, (what is shown there)
 
Last edited:

Makematics

Well-Known Member
Joined
Mar 26, 2013
Messages
1,829
Location
Sydney
Gender
Male
HSC
2013
For the first one, let z=x+iy, where x and y are real
(x+iy)^2 +2(x-iy) + 6 =0
x^2 - y^2 +2xyi + 2x -2iy + 6 = 0
Equating imaginary parts, 2xy -2y=0
xy-y=0
y(x-1)=0
x=1, y=0
Equating real parts, x^2 - y^2 + 2x +6=0
Substituting in y =0, x^2 +2x +6=0
(x+1)^2 +4=0
No real solutions.
Substituting in x=1, 1-y^2 +2 +6=0
y^2=9
y=3, y=-3
∴z=1±3i

I think this is right, but not entirely sure if my process was right with the y=0 :/ Well thats my attempt at it :p
 

Makematics

Well-Known Member
Joined
Mar 26, 2013
Messages
1,829
Location
Sydney
Gender
Male
HSC
2013
For the second one,
LHS= (1-cosnӨ) - isinnӨ
= 1- [1-2sin²(nӨ/2)] - 2isin(nӨ/2)cos(nӨ/2)
= 2sin²(nӨ/2) - 2isin(nӨ/2)cos(nӨ/2)
= -2i²sin²(nӨ/2) - 2isin(nӨ/2)cos(nӨ/2)
= - 2isin(nӨ/2) [cos(nӨ/2)+ isin(nӨ/2)]
=RHS
 

iPhone4

Member
Joined
Nov 7, 2011
Messages
167
Gender
Undisclosed
HSC
N/A
Thankyou so much! Just with Q1, why isn't it z=1+3i, 1-3i, 1+0i? Because you retrieved y=0 as a soln in the equating of the imaginary bits?
 

Makematics

Well-Known Member
Joined
Mar 26, 2013
Messages
1,829
Location
Sydney
Gender
Male
HSC
2013
Thankyou so much! Just with Q1, why isn't it z=1+3i, 1-3i, 1+0i? Because you retrieved y=0 as a soln in the equating of the imaginary bits?
No, because if you substitute z=1 back into the original equation you find that it is not a solution. and also, when i found y=0, that had nothing to do with the x=1 part. I'm not even sure if i did it right, but the fundamental theorem of algebra states that there are two solutions to the equation, and i got two which both work when substituted into the equation, so it should be fine :)
 

Makematics

Well-Known Member
Joined
Mar 26, 2013
Messages
1,829
Location
Sydney
Gender
Male
HSC
2013
for question 2(c)

Write out what u found in part (b)

Sub in z = cosθ + isinθ

Group the reals, group the imaginaries (factorise i out)

Now u would know what to do

And to show that sin(θ/2) =/= 0, observe the the RHS of what u just shown (i.e. BLAH/sin(θ/2))
I think he meant the question tells you sin(θ/2) =/= 0... but not sure. btw how will he find the answer in part (b) :/ im not sure how to do that one. i dunno if it requires sums of APs or something cos i havent learn that.
 

HeroicPandas

Heroic!
Joined
Mar 8, 2012
Messages
1,547
Gender
Male
HSC
2013
I think he meant the question tells you sin(θ/2) =/= 0... but not sure. btw how will he find the answer in part (b) :/ im not sure how to do that one. i dunno if it requires sums of APs or something cos i havent learn that.
yeh u are correcto! i misread it haha

its a geometric progression! :D



OR

 
Last edited:

Makematics

Well-Known Member
Joined
Mar 26, 2013
Messages
1,829
Location
Sydney
Gender
Male
HSC
2013
yeh u are correcto! i misread it haha

its a geometric progression! :D

hmm alright well im gonna leave it to someone else because im seriously unfamiliar with that stuff. now im defs gonna learn it because i can see it can come handy in 4 unit :)
 

iPhone4

Member
Joined
Nov 7, 2011
Messages
167
Gender
Undisclosed
HSC
N/A
Yeah I have no idea about how to do 2c. HALP! haha. Thanks.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top