R redpint New Member Joined Sep 16, 2012 Messages 18 Gender Female HSC 2013 Oct 16, 2012 #1 What are the steps used to solve this question? Find the exact length of the tangent from (4,-5) to the circle x^2 + 4x + y^2 - 2y -11 = 0.
What are the steps used to solve this question? Find the exact length of the tangent from (4,-5) to the circle x^2 + 4x + y^2 - 2y -11 = 0.
Carrotsticks Retired Joined Jun 29, 2009 Messages 9,494 Gender Undisclosed HSC N/A Oct 16, 2012 #2 I would use Pythagoras' Theorem. But you first need to complete the square to find the radius and centre of the circle.
I would use Pythagoras' Theorem. But you first need to complete the square to find the radius and centre of the circle.
R redpint New Member Joined Sep 16, 2012 Messages 18 Gender Female HSC 2013 Oct 16, 2012 #3 Thanks! Carrotsticks said: I would use Pythagoras' Theorem. But you first need to complete the square to find the radius and centre of the circle. Click to expand...
Thanks! Carrotsticks said: I would use Pythagoras' Theorem. But you first need to complete the square to find the radius and centre of the circle. Click to expand...
P paradisejessica123 New Member Joined Mar 13, 2018 Messages 4 Gender Female HSC 2019 Jul 22, 2018 #4 redpint said: Thanks! Click to expand... i tried that method and it didnt work !! ((
HeroWise Active Member Joined Dec 8, 2017 Messages 353 Gender Male HSC 2020 Jul 23, 2018 #5 It should You use distance formula for the centre(-2,1) and the point given and the radius should be 4 from there on u can use pythagoras to fin the answer
It should You use distance formula for the centre(-2,1) and the point given and the radius should be 4 from there on u can use pythagoras to fin the answer