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Math help (2 Viewers)

deswa1

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Fawun- your working is correct- textbook is wrong (unless if you copied the question wrong?)
 

Sy123

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Yeah but I get some random number.

The answer is root 7 that's why I asked.

Derp, i know how to differentiate.
The answer should be:



Either the answer is wrong or you misread the answer (or misread question). I differentiated it myself to see if you differentiated incorrectly but it is correct
 

Fawun

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Fawun- your working is correct- textbook is wrong (unless if you copied the question wrong?)
okay sweet :) and nah I didn't haha. How did you get that 1/root7 blah thing before?
 

RealiseNothing

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Okay thank you so much! It was a clear and good explanation!

Would you mind checking this question for me to see that i'm on the right track please? (can't be bothered latexing the whole thing up)



I don't know where to go next. I was thinking of factorising it but they have different powers :s

Would you be able to give me a hint as to where to go next?
For future reference if you want to factorise:







 

Fawun

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The answer should be:



Either the answer is wrong or you misread the answer (or misread question). I differentiated it myself to see if you differentiated incorrectly but it is correct
How did you get that from where I left off? :s

For future reference if you want to factorise:







wut.

WHy did you put the x (the one on the outside) into the second bracket? why not the first one?
 

deswa1

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okay sweet :) and nah I didn't haha. How did you get that 1/root7 blah thing before?
Sub in x=1- the bit on the left becomes 1(7)^-1/2 which is 1/root7
 

HeroicPandas

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Re: Math help (Because Carrot made me do this)

So how would I go in doing this question? I'm stuck :s



This is all I have so far:









Which is neither an even or an odd function.

x-intercept:







y-intercept:





vertical asymptote:





horizontal asymptote:











But I don't get it. How can x (which is infinity) be the horizontal asymptote?
y=x oblique asymptote
 

Fawun

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I've already done sum and products of roots. I just don't know how to apply it in this question :/
 

SpiralFlex

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The quadratic equation will have two roots. If I have for example a root of x=5 and x=-5, we say that these roots have the same magnitude but are opposite in sign.

So if I let two roots of the above equation be,



and



Sum of the roots:







 

Fawun

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The quadratic equation will have two roots. If I have for example a root of x=5 and x=-5, we say that these roots have the same magnitude but are opposite in sign.

So if I let two roots of the above equation be,



and



Sum of the roots:







Why didn't you do the products of them?
 

Fawun

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So we only do the ones that have the k in it?

So from all this time, i've tried to do both of it lol
 

hayabusaboston

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I am confused. How come pretty much EVERYONE on here is so passionate and enthusiastic about maths? me personally, I like and enjoy it, but somehow I feel like people here are totally engrossed in it lol. Im confused as to how there's so many maths lovers, that is all.
 

Fawun

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So we only do the ones that have the k in it?

So from all this time, i've tried to do both of it lol
Wait. How does that work then? Because for this question:



and this is what I have so far:









???

What do I do next? because there are two unknowns?
 

Fawun

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I am confused. How come pretty much EVERYONE on here is so passionate and enthusiastic about maths? me personally, I like and enjoy it, but somehow I feel like people here are totally engrossed in it lol. Im confused as to how there's so many maths lovers, that is all.
>implying that I like maths
 

SpiralFlex

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Wait. How does that work then? Because for this question:



and this is what I have so far:









???

What do I do next? because there are two unknowns?
1. Use alpha, don't interchange alphe with "a".

2. Use the product of the roots since you only get one variable.










When alpha is -2,




When alpha is 1




Hence there are two pairs of solutions:

The roots are -2, -1 or 1, 2.
 

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