J john-doe Member Joined Jul 29, 2012 Messages 179 Gender Male HSC 2012 Aug 12, 2012 #1 how would u transform y=f(x) to the graph of y=e^[f(x)] e.g. 2003 hsc q3 (a)(iv) thanks
U umm what Banned Joined Nov 6, 2011 Messages 609 Location North Ryde Gender Female HSC N/A Aug 12, 2012 #3 put up the question mate
nightweaver066 Well-Known Member Joined Jul 7, 2010 Messages 1,585 Gender Male HSC 2012 Aug 12, 2012 #4 From the paper
J john-doe Member Joined Jul 29, 2012 Messages 179 Gender Male HSC 2012 Aug 12, 2012 #5 nightweaver066 said: From the paper Click to expand... yeh so how would u transform it to e^[f(x)]
U U MAD BRO Member Joined Jul 29, 2012 Messages 287 Gender Undisclosed HSC N/A Aug 12, 2012 #6 john-doe said: yeh so how would u transform it to e^[f(x)] Click to expand... sub values of f(x) into e^[f(x)]
john-doe said: yeh so how would u transform it to e^[f(x)] Click to expand... sub values of f(x) into e^[f(x)]
nightweaver066 Well-Known Member Joined Jul 7, 2010 Messages 1,585 Gender Male HSC 2012 Aug 12, 2012 #7 john-doe said: yeh so how would u transform it to e^[f(x)] Click to expand... As x-> 1+, f(x) -> -infinity, e^[f(x)] -> 0+ As x-> +infinity, f(x) -> 0-, e^[f(x)] -> 1- As x-> 1-, f(x) -> +infinity, e^[f(x)] -> +infinity At f(x) = 2, e^[f(x)] = e^2 etc. Basically break it up and use what you know about exponentials to get the general shape of the graph and sketch.
john-doe said: yeh so how would u transform it to e^[f(x)] Click to expand... As x-> 1+, f(x) -> -infinity, e^[f(x)] -> 0+ As x-> +infinity, f(x) -> 0-, e^[f(x)] -> 1- As x-> 1-, f(x) -> +infinity, e^[f(x)] -> +infinity At f(x) = 2, e^[f(x)] = e^2 etc. Basically break it up and use what you know about exponentials to get the general shape of the graph and sketch.