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CSSA MX2 Trial (1 Viewer)

Alkanes

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So the test was today. How did everyone go?
 

iampeterr

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did anyone get the 5:3 ratio of tension D: and the last pages fucked me hard.
 

Alkanes

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I can't remember exactly what it was cos I had absolutely no idea where to start. It involved integration with limiting sums or something. :(
 

Carrotsticks

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I can't remember exactly what it was cos I had absolutely no idea where to start. It involved integration with limiting sums or something. :(
I KNEW IT.

I really hope someone from the BOS Meat (Winter one) had the CSSA as their paper for MX2. I bashed those questions into them pretty hard.
 

Sindivyn

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Thought it was a pretty easy test besides Q16. Hoping for 80ish% (skipped 13 marks of Q6).
 

bloodvial

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It was all fairly normal and fine, then bam. Last question, what even.
 

sophisms

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It was doable for most parts.... besides the last one! I basically skipped the entire question :/
 

maths lover

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the one about find the coordinates of c was also quite difficult, not sure if i got it correct.
 

maths lover

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no thats not what i did. i solved the equation simultaniously with y=c and then found the two solutions subtracted them from each other to find the length of the side and then equated it with c. however not too sure tbh.
 

MiPh

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Well, im pretty sure the y-coordinate of C was 0. So I think I got half of the answer out.
 

jeffwu95

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for the coordinates of C i got something like sqrt(1+sqrt2)
 

manscux

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Fairly good paper... stupid question with the line and the graph screwed me up....

i got parts of question 16.. but skipped 4 marks in Q16.

WTF... was that hard out equation with the sigma and than "assume infinity"

Other than that.. did good...
 

seanieg89

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does anyone remember the last question exactly?
 

manscux

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did anyone get the 5:3 ratio of tension D: and the last pages fucked me hard.
Yes... you find T1 and T2 by themselves. Than you divide. The thing you need to recognise is that tan theta = r/h. and u use that fact to simply T1/T2 to get 5:3

:)

Anybody do the sigma question ????

Last part of last question was only limiting sum so is a/(1-r) correct where a =1 and r = 4/9 (i think)???
 

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