Thanks Mod. for Nice solution.
But How can I prove the Given Result using Complex no.
Thanks
Ugh my computer froze as I was typing out the solution on LaTeX. I'll re-do it tomorrow if I have time.
But I'll get you started. Not sure how nicely De Moivre's Theorem turns out if you use the cos(x) + isin(x) = cis(x) to prove the question, but it can be done without too much difficulty if you use the complex exponential definitions of the sine function.
Try it yourself! If you are at a level to be attempting these types of integrals, I am sure you are capable of doing this.
But then again, this definition of the sine function is not within the HSC Syllabus (but good to know anyway!).
A more elementary (but consequently tougher on the algebra) method of proving this would be to realise that the series sin(x) + sin(3x) + sin(5x) + ... + sin(2k-1)x is a Trigonometric Sum with the angles in Arithmetic Progression such that a = x, and d = 2x.
There is also a closed form for such a thing. If I recall correctly, the formula is as follows: