Does anyone have anything at all which could help me learn graphs? (2 Viewers)

[bleakarcher]

One thing I am confused wif, the oblique asymptotes for x^2-4y^2=4 lolwut?

 

[AAEldar]

One thing I am confused wif, the oblique asymptotes for x^2-4y^2=4 lolwut?

This is more of a Conics question I think.. but anyway.

 

[bleakarcher]

Ah ok, I understand now. AAEldar, what did you get for your ATAR?

 

[AAEldar]

Ah ok, I understand now. AAEldar, what did you get for your ATAR?

87.45.

Glad you understand though!

 

[bleakarcher]

Yeh I thank you mate. That atar isnt too bad, but I thought you would make a 90 easy lol?

 

[AAEldar]

Yeh I thank you mate. That atar isnt too bad, but I thought you would make a 90 easy lol?

I could have (not to sound arrogant). The ATAR I got was pretty much exactly what I needed and I didn't put in nearly as much effort as I could have. In hindsight, I really only studied the day before the HSC exams for English, Physics and Engineering and they were my worst marks.

I don't care about the glory of a high mark haha, just about getting into uni and I've done that.

 

[bleakarcher]

Yeh true lol. Fuck the atar once you get into the course you want.

 

[AAEldar]

Yeh true lol. Fuck the atar once you get into the course you want.

Pretty much hahahah. Make sure you get what you need comfortably though.

 

[bleakarcher]

Yes, sir.

 

[bleakarcher]

Dude, wait, you said as x approaches infinity 4/x^2 approaches 0 but wat about the x/2?

 

[AAEldar]

Dude, wait, you said as x approaches infinity 4/x^2 approaches 0 but wat about the x/2?

We just take the limit of the as this is the part we're concerned about. Something like that... hahaha.

 

[bleakarcher]

Ah ok, I couldnt really see it, but I have to get used to it lol.

 

[cutemouse]

For

As x->infinity 4/x^2->0, So y-> +/- (1/2)x

This basically means that for large values of x, the curve tends to go near the curve/line y=+/-(1/2)x. Of course it would also approach infinity, but it will do so by staying close to y=+/-(1/2)x.