Check my integration please: (1 Viewer)

[blackops23]

integrate [(x)/(1-x)]^0.5 using x= (sin theta)^2

My answer:

inverse sine (sqrt(x)) - ((x)(1-x))^0.5

Wolfram is giving some retarded answer, please someone check for me

 

[math man]

yeh that should be right...anyways if you just differentiate your answer..check it is the original eqn just to make sure it is right if you aren't sure

 

[apollo1]

wats wolfram giving

 

[D94]

integrate [(x)/(1-x)]^0.5 using x= (sin theta)^2

My answer:

inverse sine (sqrt(x)) - ((x)(1-x))^0.5

Your answer is correct.