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2 unit maths revision (1 Viewer)

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What happened to MrBrightside's marathon thread? Anyway,

New Question:



Find the area of the shaded region.
 

Bored Of Fail

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Seriously the first time I saw that question I thought u needed 3unit circle geometry to do it, because you are given the radius , you know that a line from the centre to a chord bisects the chord, then you can find the angle AOB , then you can can find the shade area by using area of whole circle - area of minor segment
 

hscishard

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Seriously the first time I saw that question I thought u needed 3unit circle geometry to do it, because you are given the radius , you know that a line from the centre to a chord bisects the chord, then you can find the angle AOB , then you can can find the shade area by using area of whole circle - area of minor segment
Banned again. Lol
 

FriedRice1

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but none of the moderators can take a second out to do their job and ban them
 

FriedRice1

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Differentiate sec^3 (3x) with respect to x. Thats "sec cubed 3x" NOT "sec of (3x) cubed"


Should add another part to the question above, to make sure we are testing a reasonable depth of understanding and making it somewhat difficult lol.

Hence find the values of x in the domain -2pi<=x<=+2pi for which the curve y= sec^3 (3x) has stationary points
 

mitchy_boy

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Differentiate sec^3 (3x) with respect to x. Thats "sec cubed 3x" NOT "sec of (3x) cubed"


Should add another part to the question above, to make sure we are testing a reasonable depth of understanding and making it somewhat difficult lol.

Hence find the values of x in the domain -2pi<=x<=+2pi for which the curve y= sec^3 (3x) has stationary points
 

slyhunter

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but none of the moderators can take a second out to do their job and ban them
Lol, this thread is for posting questions and answers, not a diary to vent out your fail in.
 
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