Questions I don't get (1 Viewer)

[MrBrightside]

View attachment 22585

 

[Bored Of Fail 2]

use perpendicular distance formula

 

[ohexploitable]

The line is a tangent so its perpendicular distance from the centre of the the circle (the origin) is equal to the circle's radius.

 

[ohexploitable]

Alternatively, you could equate the two equations and note that the discriminant is zero and solve for r.

 

[MrBrightside]

use perpendicular distance formula

right, FARK why Didn't I see that! thanx

 

[MrBrightside]

View attachment 22586

 

[ohexploitable]

Draw it.

 

[SpiralFlex]

Enjoy, time to eat oranges!

 

[MrBrightside]

Draw it.

I Did but i fu*ked it up, so I corrected it. So thats it ay? dam i thought it would be more complex.

 

[MrBrightside]

View attachment 22597

I don't understand what (a) is asking? how do you even show that?

 

[SpiralFlex]

Here you go.





To sum up,

1. Basically you use the distance perpendicular distance formula to confirm their distances equal.

Then you have x and y, but you still need z.

2. Find the x intercept (z) by letting y = 0

3. Use the distance formula to find the sides.

4. Then the cosine rule to find the angle

5. Finally use the area of the triangle formula, 1/2 (x*y*sin z)
______________________________________________________
Note: It is a good idea to use a diagram to help you.

 

[MrBrightside]

Here you go.

View attachment 22598

View attachment 22599

To sum up,

1. Basically you use the distance perpendicular distance formula to confirm their distances equal.

Then you have x and y, but you still need z.

2. Find the x intercept (z) by letting y = 0

3. Use the distance formula to find the sides.

4. Then the cosine rule to find the angle

5. Finally use the area of the triangle formula, 1/2 (x*y*sin z)
______________________________________________________
Note: It is a good idea to use a diagram to help you.

hey thanks man, but for c, how did you get distance for XY. i got sqroot (-1-3)^2 + (0-2)^2 using then formula sqroot (x2 - x1)^2 + (y2 - y1)^2

 

[SpiralFlex]

hey thanks man, but for c, how did you get distance for XY. i got sqroot (-1-3)^2 + (0-2)^2 using then formula sqroot (x1 - x2)^2 + (y2 - y1)^2

It is Sqrt of (-1-3)^2 + (0-2)^2

= 4

By the way, what textbook did you use for these questions?

 

[MrBrightside]

It is Sqrt of (-1-3)^2 + (0-2)^2

= 4

By the way, what textbook did you use for these questions?

y am i getting sqroot 20 or 4.47?

 

[SpiralFlex]

y am i getting sqroot 20 or 4.47?

Wait, I think I did something wrong.

 

[Bored Of Fail 2]

lolz

 

[MrBrightside]

Wait, I think I did something wrong.

X is (3,2) Y is (-1,0) WHAT am i doing wrong ? i even tried urs in this thread its same thing as me, the one u did on sheet is different but i don't know how you got it. i'm using MIF.

 

[Bored Of Fail 2]

"Sqrt of (-1-3)^2 + (0-2)^2

= 4"

THATS WRONG

 

[SpiralFlex]

SORRY I GOT IT WRONG LOL! the sqrt 20 is right.

XY = SQRT 20

YZ = 5/4

XZ = (SQRT185)/4

I'll re-scan you working.

 

[cutemouse]

Where are these questions from? Just curious..