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- Feb 16, 2005
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- 2006
Check your working again, the x-intercept isn't quite correct. You're on the right track though. The trick in this is to realise that x1y1 = k since P is on the curve.I'll try the second one.
f'(x) = -k/x^2
Therefore tangent is
y-intercept:
x intercept
Area of triangle = 1/2AB
B is perp height.
Also, just because it comes from Conics in Ext2 doesn't mean that Ext1 people aren't capable of answering it. There is nothing exclusive to Ext2 required to solve this problem (i.e. a 2U method can solve this problem)