Help!! (1 Viewer)

[jovceski123]

Hey guys can yous please help me with this question. I would really appreciate the answer and worked solution or at least an explainaton of how to do it.

The slope of the line passing through the point (1.2) and perpendicular to the line ax+by+c=0 is?

A) -(a/b)

B) -1

C) b/a

D) 2

E) Not enough information is given to determain this slope.

 

[luv2luvurmama]

Hey guys can yous please help me with this question. I would really appreciate the answer and worked solution or at least an explainaton of how to do it.

The slope of the line passing through the point (1.2) and perpendicular to the line ax+by+c=0 is?

A) -(a/b)

B) -1

C) b/a

D) 2

E) Not enough information is given to determain this slope.

Slope is gradient.

The equation given can be written in the form y = mx + b (Im sure you've heard of that) Because these two equations are of a straight line. Where m is the gradient/slope and b is the y intercept

Re arrange the equation your given.
ax + by +c = 0
by = -ax - c
y = (-a/b) .x - c/b

Hence -a/b represents m and is the slope of the equations.

 

[scroates]

Yeh but the gradient of the perpendicular is needed which is -1/m.
therefore answer is b/a.

 

[luv2luvurmama]

Yeh but the gradient of the perpendicular is needed which is -1/m.
therefore answer is b/a.

Yeah i know.. lol.....

 

[jovceski123]

Dude thats exactly how i did it, but in the back of the textbook it says the answer is
C) b/a

 

[scroates]

it should cos thats the answer