• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

funky question (1 Viewer)

kwabon

Banned
Joined
May 26, 2008
Messages
646
Location
right behind you, mate
Gender
Male
HSC
2009
just wondering how would you prove this ALGEBRAICALLY, i could do it graphically not algebraically. :-S, prove; sin x - x + (1/6)x^3 >= 0 for x > 0
 

darusan92

Member
Joined
Aug 6, 2007
Messages
30
Gender
Male
HSC
2009
just wondering how would you prove this ALGEBRAICALLY, i could do it graphically not algebraically. :-S, prove; sin x - x + (1/6)x^3 >= 0 for x > 0
umm.... try differentiating it n prove that it has a positive gradient for x>0 i think they both are the same algebracally and graphically (proving positive gradient)??? just check it in case.....
 

The Nomad

Member
Joined
Oct 11, 2009
Messages
123
Gender
Male
HSC
2010
Check the inequalities exercise in Cambridge, harder 3U chapter. The last few questions are similar to this if I remember correctly. If not, I'm sure one of the examples is similar to this question.
 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,384
Gender
Male
HSC
2006
 
Last edited:

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,384
Gender
Male
HSC
2006
Edited.
 
Last edited:

lolokay

Active Member
Joined
Mar 21, 2008
Messages
1,015
Gender
Undisclosed
HSC
2009
just wondering how would you prove this ALGEBRAICALLY, i could do it graphically not algebraically. :-S, prove; sin x - x + (1/6)x^3 >= 0 for x > 0
differentiate the function, f(x) = sin x - x + (1/6)x^3
f'(x) = cosx - 1 + x^2/2
this is equal to zero when cosx = 0, so this is the minimum or maximum value f(x) in this range
and f''(x) = -sinx + x > 0 for x >0
so this is the minimum value
.'. f(x) > f(0) for x > 0
sin x - x + (1/6)x^3 > 0
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top