Trig question (1 Viewer)

[Dragonmaster262]

Evaluate lim xsinx/(1-cosx)
x->inifinite

 

[untouchablecuz]

as x->infinity, cos(x/2) fluctuates between 1 and -1

so from my working (i don't think there's anything wrong with it), there is no limit

perhaps the original limit was meant to be as x->0

 

[untouchablecuz]

that explains it

 

[jet]

God, that graph hurt my head. I think the limit should probably be x -> 0

 

[GUSSSSSSSSSSSSS]

times by (sinx/sinx) and simplify

end up with x/sinx + x/tanx
or summit like that

then apply the limit....watever it is...=S lol

 

[untouchablecuz]

disregard everything i said earlier

 

[Drongoski]

disregard everything i said earlier

I think your earlier solution with no limit is correct. If I'm not mistaken, in yr last version you don't have as denominator: lim (u -> 0) [u/tan u] = 1

Unlikely to get such limit questions in mx1, looking at past 15-yr papers.