Using the product and chain rule (1 Viewer)

[bluboy22]

Find dy/dx using the product and chain rule

y= x^2(x-5)^1/4

TIA

 

[lychnobity]

Find dy/dx using the product and chain rule

y= x^2(x-5)^1/4

TIA

y' = 2x(x-5)^1/4 + (x²)0.25(x-5)^-3/4

 

[bluboy22]

y' = 2x(x-5)^1/4 + (x²)0.25(x-5)^-3/4

Thanks, but was the chain rule used as well to get this answer?

 

[lychnobity]

Thanks, but was the chain rule used as well to get this answer?

Yeah, sorry for the rushed answer. In particular, when differentiating (x-5)^1/4 the chain rule has to be used.

ie the 2nd half of the answer

(x²)0.25(x-5)^-3/4