Q6 SBHS Trial (1 Viewer)

[shaon0]

I've done the first but i keep getting (pi/2)(e^2-3) units^3 for ii).
Any help would be appreciated. Thanks

 

[untouchablecuz]

my integral ends up being

S [e-->1] y(1-Lny)dy = (pi/2)(e^2-3) u^3

i dunno, maybe its a typo?

EDIT: using the method of slicing i got,

S [1-->0] (e^2x - 1)dx = (pi/2)(e^2-3) u^3

i think it is a typo

 

[shaon0]

my integral ends up being

S [e-->1] y(1-Lny)dy = (pi/2)(e^2-3) u^3

i dunno, maybe its a typo?

EDIT: using the method of slicing i got,

S [1-->0] (e^2x - 1)dx = (pi/2)(e^2-3) u^3

i think it is a typo

ok. I might just wait for others to do it because both of us may have made the same mistake.
Thanks for the help.

 

[kwabon]

I've done the first but i keep getting (pi/2)(e^2-3) units^3 for ii).
Any help would be appreciated. Thanks

apparently when i try opening your document, it says its corrupt, u reckon you post up the question so i can have a look.

 

[Aerath]

Which year is this from? I have the solutions to all SBHS papers....so, I'll upload it.

 

[Aerath]

But yes, I get e^2 as well:

 

[shaon0]

But yes, I get e^2 as well:

It's from 2000. If everyone is getting (pi/2)(e^2-3) it might just be a typo.

 

[shaon0]

apparently when i try opening your document, it says its corrupt, u reckon you post up the question so i can have a look.

when you download the paper, the file extension is what causes the problem most of the time. Just put an x after .doc on the documents name and it should open.

 

[Aerath]

Yup, solutions say pi/2[e^2 - 3] as well.

 

[shaon0]

Yup, solutions say pi/2[e^2 - 3] as well.

oh ok. That's good. Thanks for the help everyone.
btw, where did you get the solutions from?

 

[karasu]

can u upload the whole paper please.?