polynomials (2 Viewers)

[ozidolroks]

can someone please explain how i can do this question ?

I have the method but i don't understand it

When a polynomial P(x) is divided by x^2-4 the remainder is 2x+3. What is the remainder when P(x) is divided by x-2.


Thankx

 

[lyounamu]

can someone please explain how i can do this question ?

I have the method but i don't understand it

When a polynomial P(x) is divided by x^2-4 the remainder is 2x+3. What is the remainder when P(x) is divided by x-2.


Thankx

P(x) = (x^2-4)Q1(x) + 2x+3 ...(1)
P(x) = (x-2)Q2(x) + a

From (1) when x=2, P(2) = 7
From (2) when x=2, P(2) = a
so a= 7

remainder is 7

 

[Asubmarine]

P(x)=(x^2-4)Q(x)+2x+3
=(x+2)(x-2)Q(x)+2x+3
therefore P(x)/(x-2) = (x+2)Q(x)+(2x+3)
Remainder=2x+3
as (x-a) is (x-2) a=2
then R =2(2)+3=7

 

[lyounamu]

P(x)=(x^2-4)Q(x)+2x+3
=(x+2)(x-2)Q(x)+2x+3
therefore P(x)/(x-2) = (x+2)Q(x)+(2x+3)
Remainder=2x+3
as (x-a) is (x-2) a=2
then R =2(2)+3=7

haha love your working out.

 

[Kurwa]

Gezzz 3unit LoL =]

I did that last year xD

Uni maths is alot easier than hsc.

 

[Asubmarine]

haha love your working out.

lol, thanks. I can only hope that was genuine .
Your way would be far more efficient in a test though..

 

[annabackwards]

Gezzz 3unit LoL =]

I did that last year xD

Uni maths is alot easier than hsc.

oO What degree are you doing?