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help for physics equation.... its easy!! (1 Viewer)

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Two lightning strikes occur simultaneously 10km apart. If an observer was 3km from one strike and 7km from the other strike, find:

a) The time delay between the first light flash and second light flash reaching him. (c = 3 x 10^8 ms^-1)

b)The time delay between the sound of the closer reaching him and the more distant strike's thunder reaching him. (V sound = 340ms-1)
 

VenomP

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Two lightning strikes occur simultaneously 10km apart. If an observer was 3km from one strike and 7km from the other strike, find:

a) The time delay between the first light flash and second light flash reaching him. (c = 3 x 10^8 ms^-1)

The first lightning strike travels 3km, the second 7km.

Distance = Speed x Time

Time = Distance/Speed
= 3000m/3x10^8
= 1 x 10^-5 seconds

Similarly for the 7km strike...
= 7000m/3x10^8
= 2.33 x 10^-5 seconds

The time delay is equal to the difference in times between the two strikes. Which is equal to:

2.33 x 10^-5 seconds - 1 x 10^-5 seconds = 1.33x10^-5

For part b) the same thing applies. Replace light speed with sound speed. There you go.
 

random-1005

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Two lightning strikes occur simultaneously 10km apart. If an observer was 3km from one strike and 7km from the other strike, find:

a) The time delay between the first light flash and second light flash reaching him. (c = 3 x 10^8 ms^-1)

b)The time delay between the sound of the closer reaching him and the more distant strike's thunder reaching him. (V sound = 340ms-1)

lol, if its so easy why cant you do it genius
 
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hehe cause your the smart one pointing out that why couldnt have i done it myself genius so therefore you're the smart one hehe :p
 

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