Wait, I got it! YES! No, wait I didn't... Cambridge Question Help again (1 Viewer)

[Shadowdude]

Should I make a new thread? Might as well.



The results in Question 4 are basically:

conjg(z1+z2) = conjg(z1) + conjg(z2)
conjg(z1-z2) = conjg(z1) - conjg(z2)
conjg(z1 . z2) = conjg(z1) . conjg(z2)
conjg(1/z) = 1/conjg(z)
conjg(z1/z2) = conjg(z1)/conjg(z2)
conjg(5z) = 5 . conjg(z)

 

[untouchablecuz]

 

[Shadowdude]

Is that it? So that's how you do it... thanks!

 

[cutemouse]

It is worth noting that they don't really ask these types of questions in the HSC. But of course it is worth having a look at it.

 

[khorne]

This question is intended to help you grasp the apply the above proofs.