Unable to solve a couple of past HSC paper questions, help needed. (1 Viewer)

[Shoom]

http://www.boardofstudies.nsw.edu.au/hsc_exams/exam-papers-2007/pdf_doc/chemistry_07.pdf

Q21 c of the 2007 paper, please show working.

 

[brenton1987]

What volume of 0.005 mol L^-1 KOH is required to neutralise 15 mL of the diluted solution of H₂SO₄?

C = 0.005 mol L^-1
V = 0.0100 L
n = 0.00005 mol

n = 0.00005 mol
V = 0.1000 L
C = 0.0005 mol L^-1

C = 0.0005 mol L^-1
V = 0.0150 L
n = 0.0000075 mol

H₂SO₄ + 2 KOH --> K₂SO₄ + H₂O

n_KOH = 0.000015 mol
C_KOH = 0.005 mol L^-1
V_KOH = 0.003 L