• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Trigonometry (1 Viewer)

skillstriker

Member
Joined
Jan 19, 2012
Messages
115
Gender
Male
HSC
2013
How do you simplify:

1) sin(270-theta)
2) cos(90+theta)
3) tan(theta-180)

Full working please. Thank You!
 

bleakarcher

Active Member
Joined
Jul 8, 2011
Messages
1,509
Gender
Male
HSC
2013
Use the double angle formulae..
Fairly standard mate.

1) sin(270-a)=sin(270)cos(a)-sin(a)cos(270)=-sin(90)cos(a)-cos(90)sin(a)=-cos(a)

By similar process:

2) cos(90+a)=-sin(a)

3) tan(a-180)=tan(a)

These results are also quite obvious after observing the unit circle.
 

Timske

Sequential
Joined
Nov 23, 2011
Messages
794
Gender
Male
HSC
2012
Uni Grad
2016
1) sin(270-theta) = sin270costheta - cos270sintheta = -costheta
2) cos(90+theta) = cos90costheta - sin90sintheta = -sintheta
3) tan(theta-180) = tantheta - tan180 / 1 + tanthetatan180 = tantheta
 

nightweaver066

Well-Known Member
Joined
Jul 7, 2010
Messages
1,585
Gender
Male
HSC
2012
1. sin(270 - theta)
= sin(180 + 90 - theta)
= -sin(90 - theta)
= -costheta

2. cos(90 + theta)
= cos(180 - (90 - theta) )
= -cos(90 - theta)
= -sintheta

3. tan(theta - 180)
= tan(-(180 - theta))
= -tan(180 - theta)
= tantheta
 

skillstriker

Member
Joined
Jan 19, 2012
Messages
115
Gender
Male
HSC
2013
Thanks. I haven't learnt the double angle formula yet. So with these questions do you just have to force them into (90-theta), (180-theta), (180+theta), (360-theta)?
 

nightweaver066

Well-Known Member
Joined
Jul 7, 2010
Messages
1,585
Gender
Male
HSC
2012
I suppose so, but it's better to understand them.

E.g. For the first question, sin(270 - theta), i know that this would result in it's complementary angle as it's not starting from 180.
The result will also be negative as it's in the 3rd quadrant so it would equal to -costheta.

You can easily apply similar logic to the other questions and get the answers.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top