S sam168 New Member Joined Oct 2, 2014 Messages 7 Gender Male HSC N/A Dec 21, 2014 #1 suppose that (tanx)^2=tan(x-a)tan(x-b), show that tan2x=(2sinaxsinb)/(sin(a+b)) thank you in advance
Fizzy_Cyst Owner @ Sigma Science + Phys Goat Joined Jan 14, 2011 Messages 1,212 Location Parramatta, NSW Gender Male HSC 2001 Uni Grad 2005 Dec 21, 2014 #2 What have you done so far? To get you started: (tanx)^2=tan(x-a)tan(x-b) =[(tan(x) - tan(a))/(1+tan(x)tan(a))][(tan(x) - tan(b))/(1+tan(x)tan(b))] Last edited: Dec 21, 2014
What have you done so far? To get you started: (tanx)^2=tan(x-a)tan(x-b) =[(tan(x) - tan(a))/(1+tan(x)tan(a))][(tan(x) - tan(b))/(1+tan(x)tan(b))]