shm 3u question (1 Viewer)

[jskeza]

Hey, I don't really understand the solution. Can someone please explain it thanks (only part iii).

 

[Trebla]

Let y=v^2 and notice that all you are doing is trying to find the equation of the parabola by subsituting the points that you know lie on that parabola. That’s pretty much what the solution is doing.

 

[jskeza]

I was doing that and I got all the answers by subbing in the points to the equation and solving simultaneously.

I just wanted to know how the solution both itute and nesa get the answers straight away by looking at the graph. How do they know the particle oscillated about x=5 just by looking at it.

 

[klmtutor]

v=0 when x=3 or 7.
v=0 at end point of motion, so centre of motion must be (3 +7)/2

 

[jskeza]

v=0 when x=3 or 7.
v=0 at end point of motion, so centre of motion must be (3 +7)/2

thanks