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Well I did the entire chapter from the textbook and those were the 10 questions I didn’t get. So all of them but you can’t be bothered doing them all choose any one. Thank you in advance.Which one ?
Maybe you should rephrase that as "are unable to do". You are presenting a rather long list of questions.Well I did the entire chapter from the textbook and those were the 10 questions I didn’t get. So all of them but you can’t be bothered doing them all choose any one. Thank you in advance.
Good.I figured out Q4, Q6 and Q9. Still working on the rest
Great! Keep it upI figured out Q4, Q6 and Q9. Still working on the rest
Now before I find, I want you to note that
and thats the same as
using the log rules.
I got the same solution as you but the solution is said to be Tn= log a (2) + (4-n) log a (3). How did they get this???
Now to findwe just use the formula,
Expanding this out,
Now we can simplify further using the log rules,
Therefore,
Let's test if what we got is correct, for example if I'm looking forwhich is basically the second term in our sequence. when we substitute n=2 into the formula we obtained, we should get the second term which is
which is the same as
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simplify that and you'll getand that's correct meaning our formula works.
So![]()
Yes, apologies for the carless error. Thought the question was asking about the height of the ball from the ground expressed as the distance travelled, will edit that now. Thanks for pointing that out.Q8
Shouldn't it be?:
d1 = 8+4 = 12
d2 = 0.5 x 12 = 6
d3 = 0.5 x 6 = 3
etc
.: a = 12 r = 0.5
.: Sinf = 12/(1 - 0.5) = 24
or
after 1st drop of 8: total = 8 + (2x4 + 2x2 + 2x1 + . . . ) = 8 + 8/(1 - 0.5) = 8 + 16 = 24
I got the same solution as you but the solution is said to be Tn= log a (2) + (4-n) log a (3). How did they get this