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Timothy.Siu

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by considering the geometrical significance of (2^x - 1)/x to the graph of y = 2^x,

find:

lim (N^x-1)/x
x-->0
 

trailblazer

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It wasn't too hard. Just have to use a bit of logic.

Solution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soonSolution coming soon
 

Affinity

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the limit is log(N)
doesn't look like 2 unit
 

Affinity

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well, near 0, the numerator is roughly log(N)*x....
 

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