Well, simply...
If y = e^x
y' = 1e^x
which is just y' = e^x
Then sub in x = 3 to find the gradient (make sure you leave this in exact form as the question asks exact form i.e. m = e^3), and use point-gradient formula to find the equation.
Also find y.
I don't feel like giving the whole working out method cause it seems simple enough to do but if you wish for a full working out method then I'll write one up.