• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Primary Standard + NaOH finding concentration (1 Viewer)

smith93

Premium Member
Joined
Nov 9, 2009
Messages
11
Location
Sydney
Gender
Male
HSC
2011
hey all,

so we're doing titration in class and ive got a question about the calculations..

We're using oxalic acid as our primary standard, and we need to use it to find the concentration of our NaOH, which we made also.

So my data is,
i put 1.58g of oxalic acid in to fill a 250mL flask. so that makes it ~0.013moles.
then the molarity of that solution is 0.05 molar.
while titrating the NaOH into 25mL of the oxalic acid, it took 41.8cm^3 to reach it's equivalence point.

with that information how do i then calculate the concentration of the NaOH?!!

Thanks HEAPS!!

smithy
 

FCB

Emma Watson <3
Joined
Nov 9, 2009
Messages
563
Gender
Male
HSC
2011
Firstly you have to write a balanced equation or else it will muck up your calculations.
So i think you have a total of 0.1 molar NaOH (Were starting this at school now so i am not 100% sure)
and you have a volume so you have 3 out of 4 parts. You can now solve for 'n' (i think)

So is the answer 4mol L^-1 (most likely not.)
 

FCB

Emma Watson <3
Joined
Nov 9, 2009
Messages
563
Gender
Male
HSC
2011
I have no idea what you do about the equivalence point thing...
 

jamesfirst

Active Member
Joined
Jan 30, 2010
Messages
2,005
Gender
Male
HSC
2011
Isn't equivalence point got to do with the titration of the HCl and NaOH..

I'm still doing this in class so I probably can't answer it :S


btw what's an oxalic acid ?? The chemical formula for it.


I don't know what the hell 41.8 x10^3 cm thing is... Do you mean the scale of the burette ?

To solve these questions:

use two formulas : n = m/M and C = n/V
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top