• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Point of Inflection question (1 Viewer)

no_arg

Member
Joined
Mar 25, 2004
Messages
67
Gender
Undisclosed
HSC
N/A
Here's an odd one!
Define f to be the piecemeal function f(x)=x^2 for x>=0 and
f(x) =-(x^2) for x<=0

The graph of f is then sort of like x^3

Does f have a point of inflection at the origin?
 

conics2008

Active Member
Joined
Mar 26, 2008
Messages
1,228
Gender
Male
HSC
2005
the graph looks SIMILAR to x^3 but NOOOOOOOOOOOOOOO

because x^2 dy/dx = 2x d^2y/dx^2=2 hence no point of inflexion ??
 
Joined
Jul 7, 2002
Messages
722
Gender
Undisclosed
HSC
N/A
It changes concavity at (0,0), so this is an inflection.

But all the derivatives of order greater than 1 do not exist at (0,0).
 
Joined
Jul 7, 2002
Messages
722
Gender
Undisclosed
HSC
N/A
Some books require it to be smooth as well, and your example qualifies for this, so is not too controversial.

However other examples where it is not smooth at (a,b) may also change concavity at (a,b). This is where it gets controversial. Some books still call it an inflection, others don't.

For example,

f(x)=-x(x+1) for x &le; 0

f(x)=x<sup>2</sup> for x &gt; 0

This changes concavity at (0,0). But it is not smooth at (0,0).

Is (0,0) an inflection? Depends on the definition.
 
Last edited:
Joined
Jul 7, 2002
Messages
722
Gender
Undisclosed
HSC
N/A
But getting back to your example, I think it is a good one because the syllabus says y'' must be 0 at an inflection and change sign either side. Whilst that's OK for most examples, there will be some examples (like yours) for which it isn't true. So the syllabus's description does not suffice as a definition, yet is quite commonly used, eg., in

Bronshtein, I. N. and Semendyayev, K. A. Handbook of Mathematics, 4th ed. New York: Springer-Verlag, 2004, p. 231.

Their definition won't suffice for the example in

Purcell, E. J. and Varberg, D., Calculus with Analytic Geometry, 5th ed. Prentice-Hall, p. 166

(attached below)

nor for yours.

Purcell and Varberg just define an inflection as a point at which concavity changes. They don't have to be smooth and y' and y'' don't have to exist. The curve must however be continuous at an inflection point.
 
Last edited:

ronnknee

Live to eat
Joined
Aug 2, 2006
Messages
474
Gender
Male
HSC
2008
My Math teacher always tells us f''(x) = 0 is necessary but not sufficient proof for a point of inflexion. It must also change in concavity.

In this case, yes it does change in concavity but f''(x) does not equal to 0. Therefore there is no point of inflexion
 
Last edited:
Joined
Jul 7, 2002
Messages
722
Gender
Undisclosed
HSC
N/A
Your teacher may not be aware that there are more than 1 definition.

You'll get a different answer to no_arg's question depending on which definition you use.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top