pH question help plz (1 Viewer)

[xxshazz]

What is the pH of a 0.2mol/L solution of sulfuric acid?(assume that the acid is fully dissociated.)

how would u work this out? ty

 

[Julz666]

As sulfuric acid is diprotic (H2SO4), there will be a concentration of 0.4 moles of H+ ions in a 0.2 molar solution
thus we use the formula
pH=-logH+
pH=-log(0.4)
pH=0.699

 

[xxshazz]

pH=0.699

huh do you mean pH = 0.4 ?

 

[paul5666]

concentration of H+ is 0.4
but the pH is a logarithmic scale
i.e. pH=-log[H+]
=-log(0.4)
=0.699

use your calculator.

 

[alexx-12]

Ph means potential hydrogen
since sulfuric acid (H2SO4) has two hydrogen atoms we multiply the number of moles by two

 

[adomad]

hence if you have 0.2 moles of H2SO4 you must double it to get the moles of hydrogen ions ( from the balanced equation)

 

[unano]

-log[0.4] = 0.40 (2sf) not 0.699
use ur calculator lol.