goobi
Member
- Joined
- Oct 6, 2010
- Messages
- 196
- Gender
- Male
- HSC
- 2012
This question is from the Fitzpatrick textbook:
How many arrangements can be made of five letters chosen from the alphabet of 26 letters if no letter may be used twice in one word and no word may start with X nor with YZ in that order?
My solution:
Number of arrangements which exclude X and may include YZ at the beginning
= 25 x 24 x 23 x 22 x 21 = 6375600
Number of arrangements that start with YZ in this order
= 1 x 1 x 24 x 23 x 22 = 12144
Therefore, number of arrangements required
= 6375600 - 12144
= 6363456
However, the correct answer should be 7577856.
So can anyone please read over my solution and tell me what I did wrong?
Much appreciated!
How many arrangements can be made of five letters chosen from the alphabet of 26 letters if no letter may be used twice in one word and no word may start with X nor with YZ in that order?
My solution:
Number of arrangements which exclude X and may include YZ at the beginning
= 25 x 24 x 23 x 22 x 21 = 6375600
Number of arrangements that start with YZ in this order
= 1 x 1 x 24 x 23 x 22 = 12144
Therefore, number of arrangements required
= 6375600 - 12144
= 6363456
However, the correct answer should be 7577856.
So can anyone please read over my solution and tell me what I did wrong?
Much appreciated!