need to confirm some answers: (2 Viewers)

[fishy89sg]

i need to confirm the answers for the following questions (any correct answers will be greatly appreciated! )

7 (b) (iii) and (iv)
7 (a) (ii)
6 (a) (iv)
5 (b)
4 (a) (all)
2 (d) (ii)

thanks guys!!

 

[Legham]

for 6 a (iv) i just had pi/12 or something. i thought we'd have to use that n.pi + or - cos.alpha crap, but i think the "first pi seconds" was there to piss that off..

4 a (i) about 0.01
(ii) about 0.285
(iii) 0.4ish? can't really remember

2 d (ii) was about 533 point something.

 

[gaoOO]

i can't find my paper, so a brief description will help

i do remember that for the m values in 7, i got 0.8<m<1.2 (or something like that)
and then i got some pretty odd looking fractions in the second part, which were very long decimals.

7a)ii, i'm fairly confident that i got wrong, so i won't post up my wrong answer.

the others, i have no idea what the questions are...

crap, looking at legham's answers, i think i got the same for 4, but different answers for the others

 

[fishy89sg]

for 6 a (iv) i just had pi/12 or something. i thought we'd have to use that n.pi + or - cos.alpha crap, but i think the "first pi seconds" was there to piss that off..

yeh i had pi/4, 3pi/4, 5pi/12 and 7pi/12

4 a (i) about 0.01

yeh i had that

(ii) about 0.285

yeh i had that

(iii) 0.4ish? can't really remember

yeh i had 0.43

2 d (ii) was about 533 point something.

i had 250 less than you O_O i had 283 point something

i do remember that for the m values in 7, i got 0.8<m<1.2 (or something like that)

yeh i had that

7a)ii, i'm fairly confident that i got wrong, so i won't post up my wrong answer.

i had k = 1/(ne)

 

[gaoOO]

yeh i had pi/4, 3pi/4, 5pi/12 and 7pi/12

argh, that's not what i got. I think i got pi/4, 3pi/4, 11pi/12 and something else

i had 250 less than you O_O i had 283 point something

yeah, i got 283. something too, but i think my answer was wrong.


edit, i think my other solution was 5pi/12, so we have 3/4 solutions that are the same.

 

[sting24]

what about 7.a)ii) i got some crazy answer with "e"s

 

[gaoOO]

what about 7.a)ii) i got some crazy answer with "e"s

k = 1/ne is what fishy had and i had that too. but i thought i made an error on that one.

 

[fishy89sg]

k = 1/ne is what fishy had and i had that too. but i thought i made an error on that one.

your answers are respectable, so im assuming youre right, and thus, i am too :wave:

 

[gaoOO]

your answers are respectable, so im assuming youre right, and thus, i am too :wave:

haha, i don't trust my answers on this paper. i don't think i did that well. i was a bit short on time.

 

[fishy89sg]

did anyone get 1.28m and 0.159m for the widths of the paintball for
7 b) iv)

 

[Legham]

i had 250 less than you O_O i had 283 point something

Hmm.. well, gaa00 agrees with you, and someone in the general thoughts thread agreed with my answer We'll soon find out lol.

edit: actually, im pretty sure you're right. me and the other girl forgot to add a constant when integrating i think.

 

[Vasc0]

i need to confirm the answers for the following questions (any correct answers will be greatly appreciated! )

7 (b) (iii) and (iv)
7 (a) (ii)
6 (a) (iv)
5 (b)
4 (a) (all)
2 (d) (ii)

thanks guys!!

2dii) 284m
4ai) Just use binomial n=2
ii) Binomial again except n=20
iii) 1 - (answer in ii + Probability of 1 being green + Prob of 0 being green)

5b)4! x 3! / 6!

6aiv) There were 4 answers to this, i think pi/4, 11pi/12, 3pi / 4 and there was one more, 5pi/12

7aii) This one i got out somehow..

their y values must be equal if they share the common tanget...

ka^n = In(a)

a^n / In(a) = 1 / k

a^n = 1 / nk

And then somehow I got to n = 1 / e1 x k

7biii) 0.72 <= m <= 1.2
iv) to prove it use part i) and let x = range y = 0
and then the widths are something like 1.3 and 1.2 not too sure on that i can't remember

 

[fishy89sg]

Hmm.. well, gaa00 agrees with you, and someone in the general thoughts thread agreed with my answer We'll soon find out lol.

the question was dodgey: it said that the guy was dropping, yet he was 283m (or 533m) above the point that they dropped

 

[sting24]

i just did 7.a.ii then and got down to

nsquared = e/k

but thats not what i wrote in the exam anyway....,

yea and what the deal with 2dii????

 

[Vasc0]

the question was dodgey: it said that the guy was dropping, yet he was 283m (or 533m) above the point that they dropped

No he wasn't he was below it, the distance given was that moving downwards. It was just positive in the negative direction.

 

[fishy89sg]

No he wasn't he was below it, the distance given was that moving downwards. It was just positive in the negative direction.

Oh. Thank god i didnt act like there was something wrong.

 

[Legham]

the question was dodgey: it said that the guy was dropping, yet he was 283m (or 533m) above the point that they dropped

I think you had to take down as the positive direction.. Because a 10e^-0.2t was positive..

 

[gaoOO]

Hmm.. well, gaa00 agrees with you, and someone in the general thoughts thread agreed with my answer We'll soon find out lol.

edit: actually, im pretty sure you're right. me and the other girl forgot to add a constant when integrating i think.

i used the definite integral approach.

probably on the family one i got 1/5, did anyone else get that?

 

[vladimirv]

What was the answer to the very last question, 7 b iv)
I got something very small like 0.16, and something larger.
I managed to finish the test with about 25 min remaining, and checked my whole paper except for 7 b)
So far nothing wrong i think

 

[fishy89sg]

What was the answer to the very last question, 7 b iv)
I got something very small like 0.16, and something larger.
I managed to finish the test with about 25 min remaining, and checked my whole paper except for 7 b)
So far nothing wrong i think

yeh i had 1.28metres and 0.159metres for the two distances....

so are those answers confirmed