Need help with motion of particle question (1 Viewer)

[kevinsta]

A projectile is fired into the air
and its height in metres is given
by h = 40t − 5t^2 + 4, where t is in
seconds.

(d) What is the maximum height

 

[photastic]

Max height when dh/dt = 0. This is why at the highest point the path looks like the vertex of a parabola.
So make dh/dt = 0 and find the time it takes to reach the highest point, then subbing it back into h.

 

[randomly_generated]

Max height when dh/dt = 0. This is why at the highest point looks the path like the vertex of a parabola.
So make dh/dt = 0 and find the time it takes to reach the highest point, then subbing it back into h.

This. AND make sure you test if it is a maximum, remember a parabola could have a max or min

 

[faisalabdul16]

Max height when dh/dt = 0. This is why at the highest point the path looks like the vertex of a parabola.
So make dh/dt = 0 and find the time it takes to reach the highest point, then subbing it back into h.

Yeap!

you should get 84

 

[kevinsta]

Max height when dh/dt = 0. This is why at the highest point the path looks like the vertex of a parabola.
So make dh/dt = 0 and find the time it takes to reach the highest point, then subbing it back into h.

I thought when you make the velocity = 0 thats when it rests.

 

[photastic]

I thought when you make the velocity = 0 thats when it rests.

It also means max distance, same with max velocity when a=0

 

[braintic]

It also means max distance, same with max velocity when a=0

In both cases, there should be a 'possible' in there.

 

[kevinsta]

It also means max distance, same with max velocity when a=0

do you know how i can find how far the projectile will travel in the first 4 seconds?