Mod 5 Q (1 Viewer)

[dsakvyilsa]

Hey guys, having a bit of trouble with this one (for some reason )
I understand to find the concentrations of N2 and H2, and to set up an ICE table, with the concs of those two in the I column and the equilibrium conc of NH3 in the E column. I think my issue is the coefficients........ I thought my working seemed logical but obviously my solution didn't match that of the textbook.

Thanks

 

[Masaken]

my working out. i'm sure this is from pearson so i believe this is the answer that corresponds with the solutions

maybe check if you forgot to do c = n/v (divide the moles of each species by 5)? or when examining the changes for each species as the reaction approaches eqm, divide the change of NH3 (+0.096) by 2 for N2 and multiply by 3/2 for H2 (and these changes are -ve)

 

[dsakvyilsa]

View attachment 37182
my working out. i'm sure this is from pearson so i believe this is the answer that corresponds with the solutions

maybe check if you forgot to do c = n/v (divide the moles of each species by 5)? or when examining the changes for each species as the reaction approaches eqm, divide the change of NH3 (+0.096) by 2 for N2 and multiply by 3/2 for H2 (and these changes are -ve)

yes it's Pearson and that is the correct answer My mistake was using +0.048 as the change for NH3, rather than +0.096

thanks!