maths .. im sure this is easy but... (1 Viewer)

[myz]

hey guys..i'm sure this is easy but i cant think too well right now.. for the For the Equation: y = √2χ-3,
I know the domain is χ > 1.5, but I was just wondering what the range for that equation was?..if neone could help that would b greatly appreciated..thanks xo

 

[pLuvia]

Domain:x>1.5
Range:y>0

 

[shinji]

Domain:x>1.5
Range:y>0

indeed it is andy!

 

[sando]

domain and range questions are gay... some of the prelim stuff is way harder than HSC topics....

 

[myz]

Domain:x>1.5
Range:y>0

thankyou so much.. soz typo b4 i meant to say that the domain was greater than or = to 1.5 haha.. thanks heaps

 

[myz]

haha yeah im hoPin so..

 

[shinji]

wait a minute ...

after thinking .. shouldn't it be for all real Y values?

coz .. if you square-root a number (eg: 25) ... squaring both +5 and -5 will give you 25.

so yeah .. .. i think that:

y= all real values.

 

[milady]

nah. square roots can only be positive. that's how the operation is defined, and that's why you write +/- sqrt instead of just sqrt.
it would be written as y^2 = 2x - 3 if that were the case.

 

[pLuvia]

nah. square roots can only be positive. that's how the operation is defined, and that's why you write +/- sqrt instead of just sqrt.
it would be written as y^2 = 2x - 3 if that were the case.

Yep that's right