Maths Help (Functions) (1 Viewer)

[Redyapper]

Hi,

I'm pretty sure this is actually quite a simple question, but I just don't know how to answer it:

"A function is defined by f(x)=x^2-4x+5. What are the coordinates of the point on y=f(x) which has a gradient of 2?"

Thanks.

 

[deswa1]

Find the derivative and let it equal two- solve for x to get the x coordinate and then sub into f(x) to get the y co-ordinate. Make sense?

 

[Appleorange]

Hi,

I'm pretty sure this is actually quite a simple question, but I just don't know how to answer it:

"A function is defined by f(x)=x^2-4x+5. What are the coordinates of the point on y=f(x) which has a gradient of 2?"

Thanks.

For y=f(x) has a gradient of 2, f'(x)=2


Therefore



EDIT: I am bad with LaTex so

f(x)=x^2-4x+5
f'(x)= 2x-4
2x-4=2
2x=6
x=3

 

[Redyapper]

Thanks! Yes, it made sense and I worked it out

 

[Redyapper]

Thank you! I worked it out

 

[Appleorange]

Sorry, I am not good with LaTex

 

[Redyapper]

Sorry, I am not good with LaTex

No worries! I got what you meant

 

[iBibah]

For y=f(x) has a gradient of 2, f'(x)=2


Therefore



EDIT: I am bad with LaTex so

f(x)=x^2-4x+5
f'(x)= 2x-4
2x-4=2
2x=6
x=3

Fixed. Don't have spaces in your code, use \\ for a new line. Also you should learn to align it.

 

[Appleorange]

Fixed. Don't have spaces in your code, use \\ for a new line. Also you should learn to align it.

Oh. Thanks <3. I never knew how exactly it worked